Does anybody know why the following PHP function is not working with my XAMPP software ?
Example:
<?php
$num1 = $_POST ['Numero1'];
$num2 = $_POST ['Numero2'];
echo "El incremento del primer número es: " .$num1++;
?>
when echoing the instruction $num1++ it just copies the same number without any increment, I have tried other methods like: num$1 = num$1 + 1; but nothing seems to work. Can anybody help me ?
Thank you very much.
PHP Malfunction
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PHP Malfunction
by chtoledo » 23. February 2010 04:05
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Re: PHP Malfunction
by Altrea » 23. February 2010 06:42
$var++ is a POST-increment. Your var is been incremented after you outputed it.
you can use Pre-increment: ++$var. try if this works for you in an echo.
it is cleaner to increment your var a line earlier
you can use Pre-increment: ++$var. try if this works for you in an echo.
it is cleaner to increment your var a line earlier
- Code: Select all
<?php
$num1 = $_POST ['Numero1'];
$num2 = $_POST ['Numero2'];
$num1 = $num1 + 1;
echo "El incremento del primer número es: " .$num1;
?>
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Altrea - AF Moderator
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- Joined: 17. August 2009 13:05
- XAMPP version: several
- Operating System: Windows 11 Pro x64
Re: PHP Malfunction
by chtoledo » 23. February 2010 17:13
Thank you very much... Ill try that and let you know.
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- Posts: 4
- Joined: 23. February 2010 03:54
Re: PHP Malfunction
by chtoledo » 24. February 2010 03:43
This didn't work, do you have any other suggestions? Im using XAMPP on a Mac OS Snow Leopard....
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- Joined: 23. February 2010 03:54
Re: PHP Malfunction
by caltuna » 24. February 2010 06:23
My guess is that there is nothing or garbage in $_POST ['Numero1']
Do echo $_POST ['Numero1'];
and see what is there.
Do echo $_POST ['Numero1'];
and see what is there.
- caltuna
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- Joined: 05. May 2009 16:35
Re: PHP Malfunction
by Altrea » 24. February 2010 06:31
I haven't got a Mac OS to test.
But on my machine, it works.
Try my Test-Code:
But on my machine, it works.
Try my Test-Code:
- Code: Select all
<?php
error_reporting(E_ALL);
if ('POST' == $_SERVER['REQUEST_METHOD']) {
$num1 = $_POST['Numero1'];
$num2 = $_POST['Numero2'];
var_dump($num1, $num2);
$num1 = $num1 + 1;
echo "El incremento del primer número es: " .$num1;
}
?>
<html>
<head>
<title>Test</title>
</head>
<body>
<form action="" method="post">
<input name="Numero1" type="text" />
<input name="Numero2" type="text" />
<input type="submit" />
</form>
</body>
</html>
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Altrea - AF Moderator
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Re: PHP Malfunction
by chtoledo » 25. February 2010 00:47
The php code you sent me worked with my form, but how? and why is my original code not working? I really appreciate all your help.
Best Regards
Best Regards
- chtoledo
- Posts: 4
- Joined: 23. February 2010 03:54
Re: PHP Malfunction
by Altrea » 25. February 2010 06:34
I don't know.
I haven't got your Form-Code to test it.
Are your input fields named correct?
You can check every variable value with an echo to find out, where your variable has unexpected values.
I haven't got your Form-Code to test it.
Are your input fields named correct?
You can check every variable value with an echo to find out, where your variable has unexpected values.
We don't provide any support via personal channels like PM, email, Skype, TeamViewer!
It's like porn for programmers
It's like porn for programmers
-
Altrea - AF Moderator
- Posts: 11935
- Joined: 17. August 2009 13:05
- XAMPP version: several
- Operating System: Windows 11 Pro x64
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