imagejpeg()

Problems with the Windows version of XAMPP, questions, comments, and anything related.

imagejpeg()

Postby rusik » 23. August 2009 14:50

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Warning: imagejpeg() [function.imagejpeg]: Unable to open 'http://localhost/test/1/images/26.jpg' for writing: Invalid argument in C:\xampp\htdocs\test\1\check_image.php on line 91

On this line i have

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imagejpeg($image, $dir . '/' . $image_id  . '.jpg');


where,

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$dir ='http://localhost/test/1/images';

and $image_id is last sql query .
Why i can't use imagejpeg()? I can't create images in xampp directories(in test/1/images in my example)?How i can change permission on the folder to create images?
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rusik
 
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Re: imagejpeg()

Postby Wiedmann » 23. August 2009 15:04

Code: Select all
Warning: imagejpeg() [function.imagejpeg]: Unable to open 'http://localhost/test/1/images/26.jpg' for writing:

Why i can't use imagejpeg()?

You can't write to a HTTP location. You can only write to a local filesystem location.

I can't create images in xampp directories

Why not?
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Re: imagejpeg()

Postby rusik » 23. August 2009 15:57

Wiedmann wrote:
Code: Select all
Warning: imagejpeg() [function.imagejpeg]: Unable to open 'http://localhost/test/1/images/26.jpg' for writing:

Why i can't use imagejpeg()?

You can't write to a HTTP location. You can only write to a local filesystem location.

I can't create images in xampp directories

Why not?

gg year thanks! u write C:/xampp/htdocs/test/1/images on $dir and it works!))
And how to change permission to http account?or xampp can't do this?))it is interesting...
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Re: imagejpeg()

Postby Wiedmann » 23. August 2009 15:59

And how to change permission to http account?

Sorry, I#M not exaclty sure what you mean with this?
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Re: imagejpeg()

Postby rusik » 23. August 2009 17:16

Wiedmann wrote:
And how to change permission to http account?

Sorry, I#M not exaclty sure what you mean with this?

I want create images in xampp directories)) you wrote i can't))
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Re: imagejpeg()

Postby Wiedmann » 23. August 2009 17:25

you wrote i can't))

Regarding using a http location in imagejpeg() that's correct.
--> HTTP is a read-only protocol.
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