- Code: Select all
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<?php
$username = $_POST['username'];
$password = $_POST['password'];
if (($username == "Arjita") && (password == "sameer")){
print("Welcome Arjita");
}
else
{
print("you are not authorized to vie this ");
}
?>
</head>
<body>
<p>
<input name="username" type="text" />
</p>
<input name="password" type="text" />
<p> </p>
<p>
<input type = "Submit" name = "Submit1" value = "Login" />
</p>
<Form name ="form1" Method ="POST" Action ="C:\xampp\htdocs\Login.php">
</FORM>
</body>
</html>
Php error
2 posts
• Page 1 of 1
Php error
by arjita » 26. July 2007 17:05
Attached below is my code for a php script (it has no database look up required)..I can't get what I need to print.Also how can I encrypt the password.Any help would be appreciated ..Thanks
- arjita
- Posts: 6
- Joined: 17. July 2007 20:35
by glitzi85 » 26. July 2007 17:24
Hello,
try out this:
Normally you would not give out the formular any more if login is suceed, but for your test this is not neccessary.
For further Information please also refer to the PHP-Manual located here: http://www.php.net/manual/en/
To prevent your potentially next question: Save the File in C:\xampp\htdocs\ as Login.php (exactly in this notation!). Then open your Browser and load http://localhost/Login.php Your Site should be loaded (if you startet the Apache Webserver).
glitzi
try out this:
- Code: Select all
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?php
if(($_POST['username'] == 'Arjita') && (md5($_POST['password']) == 'd524813536b71639999ba12bdb3621a8')){
echo "Welcome Arjita";
}else{
echo "You are not authorized to view this");
}
?>
<form action="./Login.php" method="post">
Username: <input type="text" name="username">
Password: <input type="password" name="password">
<input type="submit" value="Login">
</form>
</body>
</html>
Normally you would not give out the formular any more if login is suceed, but for your test this is not neccessary.
For further Information please also refer to the PHP-Manual located here: http://www.php.net/manual/en/
To prevent your potentially next question: Save the File in C:\xampp\htdocs\ as Login.php (exactly in this notation!). Then open your Browser and load http://localhost/Login.php Your Site should be loaded (if you startet the Apache Webserver).
glitzi
-
glitzi85 - Posts: 1920
- Joined: 05. March 2004 23:26
- Location: Dahoim
2 posts
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