Xampp vs apache

[Mr_PieChee]

right. i have a very simple if:
if (isset($action) && $action == 'add') {

they i set the value to add, but on xampp it don't work yet on theschool system with have apache configured form the binary file, it works fine.

does any one have any ideas why, or it theres anything i can do to fix it?

[Wiedmann]

YOu have not an Apache problem, you have a PHP "problem". Please read the manual about "register_globals".

[Mr_PieChee]

so i have to set aciton to somehting else first? that makes no sence to me as its the page name...

[Wiedmann]

so i have to set aciton to somehting else first?

Please read:
http://de.php.net/manual/en/language.va ... ternal.php

[Mr_PieChee]

well i'm stumped! i have know idea how to fix it. i want to make the form apear if the link is clicked. its not the editing data that i have a problem with. the form won't show up:

if (isset($action) && $action == 'folder') {
?>
<form name="formfolder" action=" <?php $_SERVER['PHP_SELF']; ?>?do=addfolder" method="post">
<table><tr>
<td>Name of folder:</td><td> <input type="text" name="name" id="createname"></td></tr>
<tr><td>Description of folder: </td><td><input type="text" name="description" id="description" width="100"></td></tr>
<tr><td colspan="2" align="right"><input type="submit" name="createf" value="Create Folder"></td>
</tr></table>
</form>

etc

i just get a blank page, but ht eaddress is right

[Wiedmann]

I can not see any link or formfield with the name "action" in the HTML part.

if (isset($action) && $action == 'folder') {

So, where did you define the variable $action?

[Mr_PieChee]

arrrr.... i just used a link.. : ie
print '<center>
<a href="admin.php?action=add">Add a Photo</a> :
<a href="admin.php?action=edit">Move or Edit a photo</a> :
<a href="admin.php?action=folder">Create or remove a folder</a>
</center>';

then if teh varible has been filled in, ie the link clicked, then it works.. but it don't

[Wiedmann]

You have read the documantation from my link above?

<a href="admin.php?action=add">Add a Photo</a>

A click on a link is a GET-request. So you can refere this variable as $_GET['action'].

[Mr_PieChee]

ok, but how do i define it? i feeling realy retarded at the mo...

how do i set it equal to part of an address?

do i need to have $_GET['action'] = $action?

or go:
if ($_GET($action) && $action == 'folder') {
?

[Wiedmann]

ok, but how do i define it?

You must define nothing...:
1) External GET-variables will not automatically import to the global scope. So you have no $action, but you have $_GET['action'].

Ok, you can assign a external variable to a global one with

Code: Select all

$action = $_GET['action'];

and then work with $action in your code.

2) $_GET is a array like every other array too and you can make the same things with it.

Code: Select all

if (isset($action) && $action == 'folder') {

This should be:

Code: Select all

if (isset($_GET['action']) && ($_GET['action'] == 'folder')) {

You see, no need to import the external variable, you can work diretly with it in this simple case.

[Mr_PieChee]

ok, thanks for your help, i'll have a go now

[edit] god like... it works now.. thanks for all your help, and paitence...